Subject: Re: How far is it?
Date: Mar 11, 2004 @ 21:03
Author: acroorca2002 ("acroorca2002" <orc@...>)
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> ok in morning light it looks like we can proceed further alreadysumatra
> even without having to look for much more topographic detail
> because all the highest equatorial areas of ecuador are far
> higher as well as far steeper generally than anything on
>antipodizes
> in fact the most equatorial stripe of andean cordillera
> to the lowlands of sumatra&
> while the most equatorial highlands of sumatra antipodize to
> areas of ecuador that are not nearly so steep
>
> so it appears our quest is leading us to the highest equatorial
> pene equatorial peaks of the cordilleraequator
>
>
> a preliminary survey of ecuador at peakware etc suggests we
> have a leading candidate in mount cayambe
> which is ecuadors 3rd highest mountain
> & which offers the highest elevations in the world on the
> while peaking at only 2 minutes north latitudepeaks
>
> but there are evidently 3 others in all that cant be ruled out
>
> here are the raw & still unconfirmed data
>
> 1
> chimborazo
> elev 6310 or 6267 meters
> slat 01d28m x wlong 78d48m
>
> 2
> cotopaxi
> elev 5897 meters
> slat 00d40m x wlong 78d26m
>
> 3
> cayambe
> elev 5786 or 5780 meters
> nlat 00d02m x wlong 77d58m
>
> 4
> antisana
> elev 5752 or 5705 meters
> slat 00d29m x wlong 78d08m
> possibly close enough to stay in the running
> at the minimum bulge gradient of 477 meters per degree
> just in case there happens to be a high enough hill at the
> sumatran antipodes for the diametric length to exceed the
> diametric lengths produced from all 3 of ecuadors higher
>the
> 5 etc
> evidently all lower than 5315 meters
> which would easily disqualify them all
> even at the minimum bulge gradient of 477 meters per degree
>
>
> & tho we still dont know the actual gradient of the bulge
> it is clear that cayambe would not be overtaken by any of these
> other peaks even at the minimum gradient
> but it just isnt clear yet what boost any of the 4 diametric trials
> would get from their antipodal partner elevation in sumatra
>
> most probably not nearly enough boost to matter tho
>
>
> so for now it sure likes like the summit point of cayambe & its
> antipodal counterpart are the winners
>
> obviously tho
> more & better detail
> as well as the most exact measurement possible
> are needed before resting completely satisfied that we have
> done it
>
>
> --- In BoundaryPoint@yahoogroups.com, "acroorca2002"
> <orc@o...> wrote:
> > great
> > thanx
> > i get it
> >
> > so we should drop the circumferential pursuit
> > because even if we could determine the exact longitudes of
> > longest meridional circuitnot
> > which we cant
> > no single pair of points on that circuit would present
> themselves
> > as being any farther apart along the earths surface than any
> > other pair
> >
> > & this regardless of whether they were actually antipodal or
> > hahahahave
> >
> > & therefore we can cut back to the only chase that we still
> > left to ussumatra
> > by examining & comparing topographical maps of the
> &McManus"
> > ecuador neighborhoods
> > so as to try to find the pair of antipodes thereabouts with the
> > greatest combined elevation above sea level
> >
> > to be continued no doubt
> >
> >
> > --- In BoundaryPoint@yahoogroups.com, "Lowell G.
> > <mcmanus71496@m...> wrote:points
> > > Insertions below between lines marked thus: +++++++++
> > >
> > >
> > >
> > > ----- Original Message -----
> > > From: "m06079" <barbaria_longa@h...>
> > > To: <BoundaryPoint@yahoogroups.com>
> > > Sent: Wednesday, March 10, 2004 8:00 PM
> > > Subject: [BoundaryPoint] Re: How far is it?
> > >
> > >
> > > --- In BoundaryPoint@yahoogroups.com, "Lowell G.
> McManus"
> > > <mcmanus71496@m...> wrote:
> > > > I seem to have misconstrued the original quest as
> pertaining
> > > to tripoints.
> > > >
> > > > If it pertained to [just] points, then I think that the two
> > > farthestsea
> > > > apart diametetrically would be the two equatorial or very
> > nearly
> > > equatorial
> > > > antipodes with the greatest combined elevation above
> > > level. The bulgingelevational
> > > > equatorial diameter would easily overcome any
> > > advantages ofEcuadorian
> > > > non-equatorial points. I would nominate some
> > > peak and its Sumatran&
> > > > antipode.
> > >
> > > good thinking
> > >
> > > i also realized the diametric maximum would fall within the
> > > famous equatorial bulge
> > > just as the diametric minimum would fall within the equally
> > > famous area of polar compression
> > > but have no idea how broad or how locally steep this bulge
> > thisequator
> > > compression are
> > >
> > > like
> > > are they very nearly as linear & perpendicular as the
> &27
> > > axis themselves are
> > > being confined to say only a very few degrees of spheroidal
> arc
> > > or
> > > do they perhaps spread out much more broadly & blend
> much
> > > more gradually with their surrounding regions until finally
> > > disappearing somewhere around the 45th parallel
> > >
> > > ++++++++++++++++
> > > If the solid structure of the earth were a perfect sphere,
> > centrifugal force
> > > from the diurnal rotation would cause our fluid seas to pile
> up
> > 27 miles deep at
> > > the Equator, swamping everything there while leaving the
> polar
> > regions high and
> > > dry. Centrifugal force being what it is, the seas do pile up
> > miles deepagreement,
> > > there anyway, but the sea floors and the dry lands of the
> > equatorial regions
> > > providently bulge upward to precisely match their swell!
> Since
> > solid structure
> > > and centrifugal effects on fluid must be in perfect
> > the equatorialper
> > > bulge and the polar flats must necessarily spread broadly
> and
> > blend gradually.
> > > I doubt that the rate of bulging is constant throughout. I
> would
> > expect the
> > > rate to be greatest near the equator where the centrifugal
> force
> > is greatest.
> > > If it were constant, though, that rate would be 477 meters
> > degree ofequatorial
> > > latitude. If so, then just a few degrees of latitude from the
> > equator would
> > > negate the effects of some fairly pronounced differences in
> > relief.
> > > ++++++++++++++++
> > >
> > > if the former
> > > then you must be right on with ecuador & sumatra
> > > & we might proceed to narrow the possibilities further
> > >
> > > & if the latter
> > > then we might have to consider peaks of the entire
> > > regionof
> > > conceivably even as far afield as the tropics
> > >
> > > ++++++++++++++++
> > > It wouldn't be nearly that far.
> > > ++++++++++++++++
> > >
> > > still guessing wildly here of course
> > >
> > > in other words
> > > i do realize lowness of latitude will generally trump height
> > > altitudeit
> > > but dont know yet at what latitude this advantage begins to
> > taper
> > > off
> > >
> > > so can you think of any way to evaluate these parameters
> > > or to at least bridge the apparent data gap
> > > because i think this additional understanding could be
> > essential
> > > before proceeding further
> > >
> > > more below
> > >
> > >
> > >
> > > > The two most circumferentially distant antipodes present
> an
> > > entirely different
> > > > question. The polar flattening causes the shortest
> > > circumferential routes
> > > > between any two antipodes to be along a great circle
> through
> > > the poles.
> > >
> > > ok but thats the shortest & we want the longest
> > >
> > > ++++++++++++++++
> > > Yes, but what we want to find is the longest of the shortest
> > (most direct
> > > possible) circumferential routes--as opposed to those that
> > take unnecessarily
> > > long and scenic paths just to make themselves longer.
> > Imagine two equatorial
> > > antipodes and the question of the circumferential distance
> > between them. They
> > > could be joined by an equatorial route, a polar route, or
> > anything in between.
> > > The equatorial route would be unnecessarily long because
> > runs the bulge allwould
> > > the way around. The polar route would clearly be shortest
> > (most direct), and
> > > thus the truest answer to the question of the distance
> between
> > any pair of
> > > antipodes.
> > > ++++++++++++++++
> > >
> > > & does your next statement follow from this
> > >
> > > you seem to follow now by saying there are none shorter
> than
> > > any others
> > > which seems a contradiction of the above
> > >
> > > ++++++++++++++++
> > > What I say is that none of the most direct (polar) routes
> > differ in lengthindependently
> > > from each other on an earth without relief. They would
> certainly
> > differ from
> > > unnecessarily longer indirect (non-polar) routes.
> > > ++++++++++++++++
> > >
> > > or do both of these propositions make sense
> > >of
> > > On a
> > > > smooth oblate spheroid (an earth without relief), any pair
> > > antipodes would bedifferentiate
> > > > equally interdistant one from the other. This is because
> any
> > > imaginable great
> > > > circle connecting them would make two crossings of the
> > > bulging equatorial region
> > > > and two of the flattened polar regions. On the real world,
> only
> > > the matter of
> > > > elevational relief crossed in the process would
> > thethe
> > > distances
> > > > between any pair of antipodes. You would want to pick
> > > diametricallyhaving
> > > > opposite pair of west and east longitudes that cross the
> > > maximum amount of
> > > > continental relief during their circuit of the earth, then
> choose
> > > any two
> > > > antipodes on that circuit--perhaps something like 70° W
> and
> > > 110° E.
> > >
> > > interesting too
> > > tho i am not sure i understand
> > >
> > > are you saying here that all circumferential differences are
> > > levelled except for those presented by relief
> > >
> > > ++++++++++++++++
> > > Unfortunately, yes. I am saying that all direct polar routes
> > between any two
> > > true antipodes should be equal except for the effects of
> > intervening relief.
> > > ++++++++++++++++
> > >
> > > but in that case it seems to me we face the difficulty of
> > toimponderability
> > > measure in detail the actual terrain crossed by every
> possible
> > > great circle in the world
> > >
> > > or rather not just the difficulty but the ultimate
> &a
> > > practical impossibility of it
> > >
> > > so maybe the supposed answerability of this question
> actually
> > > evaporates under the heat of scrutiny
> > >
> > > ++++++++++++++++
> > > Yes, it does! Of course, there would be no way to effectively
> > measure such
> > > relief. One could only generalize that a route running the
> length
> > of the Andes
> > > would be considerably longer than one skimming the
> smooth
> > waters of the Pacific,
> > > etc. That is why we would probably do best to disregard
> relief
> > as a factor and
> > > simply bask in the sheer wonder of this proposition: The
> > equality of
> > > circumferential distance between any two antipodes
> > (something that we would
> > > expect to find on a perfect sphere) obtains nevertheless on
> our
> > oblately
> > > spheroidal earth! End of my insertions.
> > > ++++++++++++++++
> > >
> > > but i am sure i dont fully understand this yet
> > > so please clarify further if you can
> > >
> > > thanx
> > >
> > > end insertions
> > >
> > > >
> > > > Lowell G. McManus
> > > > Leesville, Louisiana, USA
> > > >
> > > >
> > > > ----- Original Message -----
> > > > From: "acroorca2002" <orc@o...>
> > > > To: <BoundaryPoint@yahoogroups.com>
> > > > Sent: Wednesday, March 10, 2004 12:41 PM
> > > > Subject: [BoundaryPoint] Re: How far is it?
> > > >
> > > >
> > > > > in bp terms
> > > > > you have improved as well as redeemed what was only
> > tryquest
> > > > > pointing quest by turning it into an actual tripointing
> > > > >own
> > > > > moreover your upgraded version is interesting in its
> > rightfor
> > > > >
> > > > > & it holds forth some promise of being ultimately
> > answerable
> > > too
> > > > >
> > > > >
> > > > > so have a leading pair of candidates suggested
> > themselves
> > > yet
> > > > >
> > > > >
> > > > >
> > > > > & having tried a few things too
> > > > > i can report that the original quest
> > > > > namely
> > > > > which points on earth are farthest apart
> > > > > & exactly how far apart are they
> > > > > remains as hard to make any real headway with as it is
> > hard
> > > to
> > > > > improve upon in curiosity value & elegance
> > > > >
> > > > >
> > > > > --- In BoundaryPoint@yahoogroups.com, "Lowell G.
> > > McManus"
> > > > > <mcmanus71496@m...> wrote:
> > > > > > If one wanted to determine the two tripoints that are
> > farthest
> > > > > apart, one should
> > > > > > first determine which few pairs are the most likely
> > > candidates
> > > > > based on their
> > > > > > relative antipodality from each other. This would take
> > some
> > > > > trial and error.
> > > > > > However, since the antipodes of most continents are
> > > oceanic,
> > > > > there shouldn't be
> > > > > > an abundance of likely candidates.
> > > > > >
> > > > > > Next, the few candidates might have to be evaluated
> > theis
> > > > > effects of the
> > > > > > spheroidicity of the earth and for elevation. The earth
> > anEquator
> > > > > oblate spheroid,
> > > > > > bulging at the Equator and flattened at the poles.
> > However,
> > > the
> > > > > difference
> > > > > > between sea level diameters pole-to-pole and
> tomost
> > > > > Equator is typically
> > > > > > stated in the range of 40 to 43 km. The supposedly
> most
> > > > > precise model pegs the
> > > > > > figure at 42,952 meters, which is less than 27 miles.
> On
> > > top of
> > > > > this distance,
> > > > > > elevation could add a few more miles if one found a
> pair
> > of
> > > > > relatively antipodal
> > > > > > tripoints both in high mountains. Elevation would
> > > affectantipodes
> > > > > diametric
> > > > > > distance and would be much less significant
> > > circumferentially.
> > > > > >
> > > > > > Considering the relative paucity of land-land
> > andenter
> > > the
> > > > > relative paucity
> > > > > > of tripoints near the poles, the variations due to
> > > spheriodicity
> > > > > and elevation
> > > > > > above sea level would probably be inconsequential in
> > > > > determining the two most
> > > > > > interdistant tripoints.
> > > > > >
> > > > > > At http://williams.best.vwh.net/gccalc.htm , you will find
> yet
> > > > > another
> > > > > > great-circle distance calculator into which one can
> > theapart.
> > > > > coordinates of any
> > > > > > two points and get their circumferential distance
> > > Thisanswers
> > > > > calculator
> > > > > > differs from the others in that you can chose from
> various
> > > > > mathematical models
> > > > > > of the shape of the earth, from perfectly spherical
> through
> > a
> > > > > number of
> > > > > > spheroidal models. Among these last, the one
> currently
> > > > > accepted is
> > > > > > WGS84/NAD83/GRS80.
> > > > > >
> > > > > > Lowell G. McManus
> > > > > > Leesville, Louisiana, USA
> > > > > >
> > > > > >
> > > > > >
> > > > > > ----- Original Message -----
> > > > > > From: "acroorca2002" <orc@o...>
> > > > > > To: <BoundaryPoint@yahoogroups.com>
> > > > > > Sent: Wednesday, March 10, 2004 8:31 AM
> > > > > > Subject: [BoundaryPoint] Re: How far is it?
> > > > > >
> > > > > >
> > > > > > > really
> > > > > > > i dont remember that
> > > > > > >
> > > > > > > & it is an interesting question
> > > > > > > as well as a challenging try pointing quest
> > > > > > >
> > > > > > > perhaps even 2 of each
> > > > > > > since the farthest pair of points measured
> > > circumferentially
> > > > > > > might not be the same points as the diametrically
> > farthest
> > > > > pair
> > > > > > >
> > > > > > >
> > > > > > > yet exactly how to solve for either set
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > alternatively
> > > > > > > someone may already have solved & posted
> > fora
> > > > > them
> > > > > > >
> > > > > > > so perhaps a prior question is
> > > > > > > exactly how to search for any such ready made
> > answers
> > > > > > >
> > > > > > >
> > > > > > > &or
> > > > > > > failing that
> > > > > > > there must be some data on the geoid already
> > developed
> > > &
> > > > > > > available somewhere that might be useful toward
> these
> > > > > ends
> > > > > > > if we knew what to look for
> > > > > > >
> > > > > > > like
> > > > > > > greatest circumference & diameter figures might be
> > > good
> > > > > > > place to start
> > > > > > > since these are likely to have been worked out to
> some
> > > > > degree
> > > > > > > of specificity & accuracy
> > > > > > >
> > > > > > > but where & how to find them
> > > > > > >
> > > > > > > & could we in fact approach the correct answers via
> > these
> > > > > data
> > > > > > >
> > > > > > > & if so
> > > > > > > by exactly what means could we get there from here
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > but can anyone solve or advance this
> > > > > > >
> > > > > > > or even clearly see the right way to go
> > > > > > >
> > > > > > >
> > > > > > > --- In BoundaryPoint@yahoogroups.com, "L. A.
> > Nadybal"
> > > > > > > <lnadybal@c...> wrote:
> > > > > > > > We discussed some time back the maximum
> > distance
> > > that
> > > > > any
> > > > > > > two places
> > > > > > > > on earth could be from one another.
> > > > > > > >
> > > > > > > > This site claims to deliver the distances between
> two
> > > > > selected
> > > > > > > points:
> > > > > > > >
> > > > > > > > www.indo.com/distance/
> > > > > > > >
> > > > > > > > LN
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > Yahoo! Groups Links
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > >
> > > > >
> > > > >
> > > > >
> > > > > Yahoo! Groups Links
> > > > >
> > > > >
> > > > >
> > > > >
> > > > >
> > > > >
> > >
> > >
> > >
> > >
> > >
> > > Yahoo! Groups Links